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The Old Testament account of Noah (Gen. 6:9 - 9:19) states that the LORD instructed Noah to build a large arc (boat) in order to preserve different animal species from the great flood that was to come. The dimensions of the arc are described in Gen. 6:15:

This is how you are to make it: the length of the ark three hundred cubits,
its breadth fifty cubits, and its height thirty cubits.

a. Assuming that the arc was essentially in the shape of a rectangular prism (box), and that all the space was usable, what would have been the volume of the arc in cubic feet (note: one cubit is about 1.5 ft in length).

b. A Toyota Camry is about 12 ft long by 6 1/2 ft wide by 5 1/2 ft. high. Assuming that

2007-10-01 04:37:37 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

Assuming that the cars could be stacked up with no wasted space, how many Toyotas would have fit inside Noah's ark?

2007-10-01 04:38:44 · update #1

2 answers

V= h*w*l
V (arc)=300*1.5 * 50*1.5 * 30*1.5 = 1,518,750 cu ft
V(Camry)=12*6.5*5.5 = 429 cu ft
V(arc)/V(Camry) =1,518,750 cu ft / 429 cu ft =3540.209 or 3540 Camrys

2007-10-01 04:49:29 · answer #1 · answered by 037 G 6 · 2 0

450*75*45= 1518750 ft^3

t= 12*6.5*5.5= 429 ft^3

1 518 750 / 429 = 3540 liquid volumes of Camrys rounded to the nearest Camry.

Several other logistic computation experiments involving reorientation are necessary if Camry solid shapes are to be considered. each of the three dimensions (units) of camrys would be compared to the same of those of the arc to determine how many camrys would fit in the arc.

Calculations could be greatly reduced by creating a scale mockup and working it manually.

2007-10-01 12:12:31 · answer #2 · answered by Anonymous · 0 0

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