M is the midpoint of CF for the points C(3, 7) and F(9, 3). Find MF.
2007-10-01 03:34:33 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
CF = √[(3-9)² + (7-3)²] = √40 = 2√10, and MF is half that, or just √10.
2007-10-01 03:39:35 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
M's co-ordinates are the averages of C and F which means it is at ( (3+9)/2 , (7+3)/2 ) = (6,5). This means MF is (6,5) to (9,3)
2007-10-01 03:40:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
M = (3+9)/2 , (7+3)/2 = (6,5)
MF = V(2x2)+(4x4) = V4+16 = v20 = 2V5
2007-10-01 03:48:50 · answer #3 · answered by Kid 3 · 0⤊ 0⤋
M= (x1 + x2)/2,(y1 + y2)/2
=(3+9)/2,(9+3)/2
=12/2,12/2
=(6,6)
MF = sqrt((9-6)^2 + (3-6)^2)
=sqrt(9+9)
=4.24
I'm not sure though
2007-10-01 03:42:18 · answer #4 · answered by Atieno 3 · 0⤊ 0⤋
m(6,5)
2007-10-01 03:40:31 · answer #5 · answered by crankdat.kellyanne 1 · 0⤊ 0⤋