Find the distance between the points (23,-18) and (30,-15). Also find the midpoint of the segment that joins the points.
What is the distance?
(type an exact answer, using radicals as need.)
What is the midpoint?
(type an ordered pair. type an integer or a simplified fraction.)
2007-10-01 01:52:37 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
distance
sqrt ((23-30)^2 + (-18 - (-15))^2
sqrt (49 + 9)
sqrt 58
midpoint is halfway between each of the x and the y points
(23+30)/2, (-18+(-15)/2
26.5, -16.5
2007-10-01 02:12:00 · answer #1 · answered by Maverick 7 · 1⤊ 0⤋
x changes 7 and y changes 3
distance = sq root (3^2 + 7^2) using Pythagorus
= sq root (9 + 49) = sq root (58)
midpoint (26.5, -16.5)
2007-10-01 02:12:00 · answer #2 · answered by Beardo 7 · 0⤊ 0⤋
formula for distance :
SQRT( (x2-x1)^2 + (y2-y1)^2 )
SQRT( (23-30)^2 + (-18- -15)^2 )
SQRT( (-7)^2 + (-10)^2)
SQRT( 49 + 100 )
SQRT( 149 )
Distance= 12.206555615733702951897855256623 units
Midpoint:
(x+x)/2 = new x
(y+y)/2 = new y
(23+30)/2 = new x
new x = 26.5
(-18 + -15)/2 = new y
new y = -6.5
Midpoint = (26.5, -6.5)
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2007-10-01 02:11:54 · answer #3 · answered by Anonymous · 0⤊ 2⤋
1) 2Root14
2)( 53/2 , 33/2 )
2007-10-01 01:59:50 · answer #4 · answered by Anonymous · 0⤊ 1⤋