I've been doing (x)+(x+2)+(x+4)+(x+6)=-46 and trying to solve from there. It never comes out right! Could you please show me the steps? Thanks!
2007-10-01 00:03:13 · 5 answers · asked by ♫ ∫aoli 4 in Science & Mathematics ➔ Mathematics
x + (x + 1) + (x + 2) + (x + 3) = - 46
4x + 6 = - 46
4x = - 52
x = - 13
- 13 , - 12 , - 11 , - 10 is answer.
2007-10-01 04:21:38 · answer #1 · answered by Como 7 · 1⤊ 0⤋
You used the wrong equation, since its consecutive integer its only x, x+1, x+2 and x+3. You only use x, x+2, x+4 and x+6 when it is consecutive odd or even integer.
let x be the first integer
x + (x+1) + (x+2) + (x+3) = -46
4x + 6 = -46
4x = -46 - 6
4x = -52
x = -13
Therefore the smallest integer is -13.
2007-10-01 07:12:51 · answer #2 · answered by stevenson_yu727 2 · 0⤊ 0⤋
That would be because you should be doing
x + x+1 + x+2 + x+3 = -46
4x + 6 = -46
4x = -52
x = -13
-13 + -12 + -11 + -10 = -46
2007-10-01 07:20:47 · answer #3 · answered by Edgar Greenberg 5 · 0⤊ 1⤋
Four consecutive integers, not four consecutive ODD or EVEN integers.
x + (x+1) + (x+2) + (x+3) = -46
4x + 6 = -46
4x = -52
x = -13
The smallest integer is -13
The numbers are -13, -12, -11 and -10
(-13) + (-12) + (-11) + (-10) = -46
2007-10-01 07:10:46 · answer #4 · answered by gudspeling 7 · 1⤊ 0⤋
try
(x)+(x+1)+(x+2)+(x+3)=-46
4x=-46-6
4x=-52
x=-13
-13-12-11-10=-46
answer: -13
not sure... ^_^
2007-10-01 07:13:17 · answer #5 · answered by Basil E 2 · 0⤊ 0⤋