A billiard ball,.008kg at a speed of 10m/s hits another ball at rest after impact. The 2 balls move at an angle of 30degrees in the x axis. Find the speed of the balls after impact?
2007-09-30 23:34:20 · 1 answers · asked by clickfalcon 2 in Science & Mathematics ➔ Physics
The sum of moments before collision = sum of moments after collision (assuming a perfect elastic collision)
Px=P'x
Py=P'y
since m1=m2=m
Px=mVx1 + mVx2= mVx1
P'x=mV'x1 + mV'x2
Py=mVy1 + mVy2= 0
P'x=mV'y1 + mV'y2
Since "The 2 balls move at an angle of 30degrees in the x axis" I'm assuming that one makes 30 degrees and the other makes -30 degrees.
mVx1=mV'x1 + mV'x2 and
0 = mV'y1 + mV'y2
Vx1=V'x1 + V'x2=2V'x1
or V'x=0.5 Vx= 10/2=5m/s
0 = V'y1 + V'y2 => V'y1= - V'y2
Also
tan(A)=Vy'/Vx'
V'y=tan(30) V'x=2.9 m/s
2007-10-01 06:52:45 · answer #1 · answered by Edward 7 · 0⤊ 0⤋