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H (x) = (4 x^2 + 5 x^-4 )^3

H ' (x) =

2007-09-30 20:21:00 · 2 answers · asked by Rrrr0001 1 in Science & Mathematics Mathematics

2 answers

H `(x) = 3 [ 4 x ² + 5 x^(- 4) ] ² [ 8x - 20 x^(- 5) ]

2007-09-30 23:15:34 · answer #1 · answered by Como 7 · 0 0

You need to use the Chain Rule.
H'(x) = (8x - 20x^(-5))*3(4x^2 + 5x^(-4))^2.

2007-09-30 20:26:46 · answer #2 · answered by visible_fred 2 · 0 0

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