A compound has the empirical formula CHCl. A 256-mL flask, at 373 K and 750 torr, contains 0.800 g of the gaseous compound. Give the molecular formula.
256 mL = .256 L, 373 K, 750/760 = .987 atm
PV = nRT = (.987)(.256) = n(.08206)(373) ---> n = .008 mols
CHCl, MW = 48.648 g/mol ---> (.80g)/(48.648 g/mol) = .016
(.016)/(.008) = 20
C20H20Cl20 = Molecular Formula.
Is this right?
2007-09-30 18:13:45 · 2 answers · asked by the Jam 2 in Science & Mathematics ➔ Chemistry
well the calculations seem correct at a glance, but i doubt that a compound with a molecular weight that high would be a gas.
oh, i see... (.016)/(.008) = 2 (not 20). that's better!
the gas then is C2H2Cl2 - dichloroethene. it has a boiling point of 50-60 degrees C so at 100 degrees C it would indeed be a gas.
2007-09-30 18:22:47 · answer #1 · answered by vorenhutz 7 · 0⤊ 0⤋
yes but your fraction is upside down
2007-10-01 01:21:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋