Y=x^3-6x^2+32 need some help with my cal?

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Y=x^3-6x^2+32 need some help with my cal?

can someone please help me and if possible give me a step by step answer

2007-09-30 18:08:45 · 2 answers · asked by joemelle k 2 in Science & Mathematics ➔ Mathematics

2 answers

don't really know what your asking for but if you're talking bout derivatives then it would be Y'=3x^2-12x.

the integral would be (1/4)x^4-2x^3+32x+c

2007-09-30 18:49:45 · answer #1 · answered by shadoyaj 4 · 0⤊ 0⤋

You have not asked a question.
dy/dx = 3xÂ² - 12x
dÂ²y/dxÂ² = 6x - 12
May be of use?

2007-10-01 02:39:12 · answer #2 · answered by Como 7 · 0⤊ 0⤋