sin (theta) = 0.6000
1. sin (pi - theta) = ?
How do you know where to start in quadrant?
2007-09-30 17:42:32 · 5 answers · asked by SUPERMAN 2 in Science & Mathematics ➔ Mathematics
sin Ɵ = 0.6 (is + ve)
Ɵ in 1 st and 2 nd quadrants
Ɵ = 36.9° , 143.1°
sin (π - Ɵ ) = sin π cos Ɵ - cos π sin Ɵ
sin (π - Ɵ ) = 0 - (-1) sin Ɵ
sin (π - Ɵ ) = sin Ɵ
sin | All
--------- >>>>>>>is used to give signs.
tan | cos
All are------- +ve in 1st quad.
sin is------- +ve in 2nd quad.
tan is------ + ve in 3rd quad
cos is----- +ve in 4th quad.
2007-09-30 19:59:05 · answer #1 · answered by Como 7 · 0⤊ 0⤋
sin (theta)=0.6>0 means theta must be in quadrant 1or2(where sin>0).
then draw the unit circle and reflect theta about the cos-axis then add pi to that angle
we will have that sin(pi-theta)=sin(theta)=0.6
2007-09-30 17:53:18 · answer #2 · answered by Finnergan Ho 2 · 0⤊ 0⤋
sin a = sin (pi - a). (i wrote a coz its faster than theta)
Its a trig formula. So sin (pi-a) also = 0.6 (any particular reason for the zeros?)
Type it into your calculator.
2007-09-30 17:50:52 · answer #3 · answered by mevelyn2551 3 · 0⤊ 0⤋
sine is positive in 1st (0-90)quadrant and 2nd (90-180)quadrant.....
so
case θ<90 :
sin θ =1st quandrant
sin Π-θ =2nd quad
...............
sin θ=0.60 (θ=36.87, so 1st quad)
sin (180-θ)=0.60(180-θ=180-36.87=143.13, so 2nd quad)
fine !!
hope i made u clear
2007-09-30 18:13:36 · answer #4 · answered by Mark Federer 2 · 0⤊ 0⤋
is 0.6000 in degrees or radians?
2007-09-30 17:55:53 · answer #5 · answered by garlin104300 1 · 0⤊ 0⤋