algerbra question?

Question

use the substitution method to solve the linear equation;

y= -3x - 1
x - 3y = 3

x - 2y = 8
y = -4x - 5

Answer 1

The 1st one:
y=-3x-1

x-3y=3
x=3+3y

back to the y=-3x-1 (substitute the x with 3+3y)
y=-3(3+3y)-1
y=-9-9y-1
y=-10-9y
y+9y= -10
10y= -10
y= -1
then, x=3+3y = 3 + (3 x -1) = 3 -3 = 0

The 2nd one:
y= -4x -5
x -2y = 8
x -2(-4x -5)=8
x +8x +10 = 8
9x = 8-10
9x = -2
x = -2/9

y= -4 (-2/9) -5
y= 8/9 -5
y= 37/9 = -4 1/9

Answer 2

In one pair of equations, x and y stand for the same quantities in both equations. In the first equation, the value of y is equal to the value of -3x - 1. So take the second equation and put (-3x - 1) in place of any place that has a y. In other words, x - 3(-3x - 1) = 3. Your equation now has only one variable, x. Solve the equation for x. Then take that value and go back to the first equation, where we said that y = -3x - 1. Since you now know the value of x, you can get the value of y.

Answer 3

y = -3x -1

x - 3y = 3
so x - 3(-3x -1) = 3
x + 9x + 3 = 3
10x = 0
x = 0
y = -1


x - 2y = 8 and y = -4x -5
x - 2 (-4x -5) = 8
x + 8x + 10 = 8
9 x = -2
x = -2/9

y = - 4 1/9

Answer 4

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