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e^0.006x = 28

2007-09-30 17:23:46 · 5 answers · asked by finitemathkid 1 in Science & Mathematics Mathematics

So what is the solution set?

2007-09-30 17:33:32 · update #1

5 answers

0.006 x = ln 28
x = ln 28 / (0.006)
x = 555.4 (to 1 decimal place)

2007-10-01 10:49:15 · answer #1 · answered by Como 7 · 2 0

Take the natural logarithm of both sides:

0.006x = ln 28

Then treat ln 28 as a constant, which it is, and solve for x (i.e., divide both sides by 0.006) to find out what x is.

28 is not 7^2, so jruzzy's substitution ln 28 = 2 ln 7 is incorrect.

2007-10-01 00:29:04 · answer #2 · answered by devilsadvocate1728 6 · 1 1

Taking the natural log of both sides, you get:

0.006x = ln 28

x = ln 28 / 0.006

You can further simplify:

x = 2 ln 7 / 0.006
x = ln 7 / 0.003

2007-10-01 00:28:18 · answer #3 · answered by jruzzy 2 · 0 1

how do you know it's a logarithmic natural problem??? you must understand the mechanics of solving this problem don't you?

2007-10-01 00:26:53 · answer #4 · answered by Anonymous · 0 0

take ln of both sides u'll get
.006x= ln28
x= 555.4

2007-10-01 00:30:37 · answer #5 · answered by ehgirl 2 · 1 1

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