e^0.006x = 28
2007-09-30 17:23:46 · 5 answers · asked by finitemathkid 1 in Science & Mathematics ➔ Mathematics
So what is the solution set?
2007-09-30 17:33:32 · update #1
0.006 x = ln 28
x = ln 28 / (0.006)
x = 555.4 (to 1 decimal place)
2007-10-01 10:49:15 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Take the natural logarithm of both sides:
0.006x = ln 28
Then treat ln 28 as a constant, which it is, and solve for x (i.e., divide both sides by 0.006) to find out what x is.
28 is not 7^2, so jruzzy's substitution ln 28 = 2 ln 7 is incorrect.
2007-10-01 00:29:04 · answer #2 · answered by devilsadvocate1728 6 · 1⤊ 1⤋
Taking the natural log of both sides, you get:
0.006x = ln 28
x = ln 28 / 0.006
You can further simplify:
x = 2 ln 7 / 0.006
x = ln 7 / 0.003
2007-10-01 00:28:18 · answer #3 · answered by jruzzy 2 · 0⤊ 1⤋
how do you know it's a logarithmic natural problem??? you must understand the mechanics of solving this problem don't you?
2007-10-01 00:26:53 · answer #4 · answered by Anonymous · 0⤊ 0⤋
take ln of both sides u'll get
.006x= ln28
x= 555.4
2007-10-01 00:30:37 · answer #5 · answered by ehgirl 2 · 1⤊ 1⤋