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say for instance their is a 1.91N block on a 16 degree incline. It is pushed and moves down the board at a constant speed (no accleration) how do I go about calcualting the coefficient of kinetic friction

2007-09-30 16:29:11 · 2 answers · asked by akanthasy 1 in Science & Mathematics Physics

2 answers

Sum of forces must be zero if it moved with a constant speed
or force of friction f equal to downward force F.

so F=f
where
f=uN
N=W cos(16)
F= W sin(16)

u W cos(16) = W sin(16)
finally
u=tan(16)
u=.287

2007-09-30 17:00:16 · answer #1 · answered by Edward 7 · 0 0

think of touching directly to the acceleration using gravity, it is approximately 9.8. Now think of roughly forces. There are continually 2 forces appearing on an merchandise gravity and customary tension. jointly as the gravity is pulling the ball down, the traditional tension iS pushing it up, type of, perpendicular to the incline. So jointly as the gravity is pulling it down the traditional tension is somewhat bent based upon the perspective, the extra it is bent the quicker it is going

2016-10-20 10:40:32 · answer #2 · answered by ? 4 · 0 0

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