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gravity on mercury is .38 the amount it is on earth

2007-09-30 15:06:29 · 1 answers · asked by Anonymous in Science & Mathematics Physics

k thats pretty complicated but the last line helps a lot thnx

2007-10-01 12:11:59 · update #1

1 answers

vx = hor. v, vy = vert. v
Distance = vx*time.
Time = time up + time down = 2*vy/g
Thus distance = 2*vy*vx/g, in other words it's inversely proportional to g for a given launch velocity and angle.
Answer = 10 ft/0.38

2007-10-01 04:58:53 · answer #1 · answered by kirchwey 7 · 0 0

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