Write the equation of the line passing through (–1, –3) and (2, –3).
2007-09-30 14:33:38 · 5 answers · asked by Jessica B 1 in Science & Mathematics ➔ Mathematics
y= -3
because u r finding the y intercept
2007-09-30 14:41:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You're probably looking for something like y = mx +b. So, use the two points to find the slope (m) by dividing the change in y values by the change in x values. So m = (-3 - -3) / (2- -1) = 0. Then, use one of the points to find the y-intercept (b). So, if I use the first point, y is -3. Use the point in the y = mx + b form, you'll have -3 = 0 *-1 + b. Then you solve for b, which = -3. So the equation that passes through the two points is y = -3.
2007-09-30 21:51:14 · answer #2 · answered by db 1 · 0⤊ 0⤋
The form you are most likely looking for is slope-intercept form: y=m*x + b where m is the slope and b is the point at which the equation crosses the y intercept.
m = slope = (change in y) / (change in x)
(-3 - -3) / (2 - -1) = 0 / 3 = 0
y = 0 * x + b
-3 = 0 * -1 + b
b = -3
y = -3
2007-09-30 21:38:54 · answer #3 · answered by lhvinny 7 · 0⤊ 0⤋
y = -3
2007-09-30 21:37:59 · answer #4 · answered by God 2 · 0⤊ 0⤋
Use the intercept equation,
(y2-y)/(x2-x) = (y2-y1)/(x2-x1)
(-3-y)/(2-x) = (-3-(-3))/(2-(-1))
the right hand side vanishes,
-3 - y = 0
y = -3, (ans.)
2007-09-30 21:42:46 · answer #5 · answered by jhez 2 · 0⤊ 0⤋