An engine is working at 500 Joules and it has a capacity of 750 Joules what would the ration be?

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An engine is working at 500 Joules and it has a capacity of 750 Joules what would the ration be?

3/5x100
2/5x100
2/3x100
100%

2007-09-30 13:51:50 · 2 answers · asked by chato r 1 in Science & Mathematics ➔ Physics

2 answers

None of them, as you've written them. Since 500/750 = 2/3, the answer is

2/3*100%

The % sign makes a big difference, since it means "divide by 100". 2/3*100 = 66.67, which is an impossibly high efficiency. However, 2/3*100% = 0.6667, which is a reasonable efficiency.

2007-09-30 13:56:08 · answer #1 · answered by lithiumdeuteride 7 · 0⤊ 0⤋

2/3*100% is the answer. means your engine is running 2/3 only of its capacity or 66.667%. That is if you mean that factor 100 is expressed in %.

2007-09-30 21:08:14 · answer #2 · answered by Spiral88 1 · 0⤊ 0⤋