Neither, it would be 2x^3.
2007-09-30 13:45:58
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answer #1
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answered by Pete 2
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Neither.
(x^3) + (x^3) = x*x*x + x*x*x = 2*(x*x*x) = 2*(x^3)
Think of adding exponents as if you were just adding/subtracting variables. You cannot add together x+y, so you cannot add together exponents when adding/subtracting. Remember your order of operations: parenthesis, exponents, multiply/divide, add/subtract
You can always check your work by using some small numbers:
if x = 2:
2^3 = 2*2*2 = 8
2^6 = 2*2*2*2*2*2 = 64
2^9 = 2*2*2*2*2*2*2*2*2 = 512
(2^3) + (2^3) = (8) + (8) = 16 = 2*8 = 2*(2^3)
if x=3
3^3 = 27
3^6 = 729
3^9 = 19683
(3^3) + (3^3) = 27 + 27 = 54 = 2*27 = 2*(3^3)
I think you were getting confused with multiplication:
(x^3) * (x^3) = x^(3+3) = x^6
(x*x*x) * (x*x*x) = x*x*x*x*x*x = x^6
2007-09-30 21:02:30
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answer #2
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answered by mrvadeboncoeur 7
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Neither, it'll be 2x^3.
Here's the only ways those can happen:
(x^3)^3 = x^(3*3) = x^9
x^3 * x^3 = x^(3+3) = x^6
2007-09-30 20:46:22
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answer #3
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answered by jthereliable 3
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neither.
When you add them its like saying 4 + 4 = 8 which is really (2)(4)
so x^3 + x^3 = (2)(x^3)
2007-09-30 20:47:50
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answer #4
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answered by Anonymous
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the numerical coefficient of x^3 is understood to be one,
so one + one = two. Therefore the correct answer is:
2x^3
You can add terms if they are similar or they have the same variables, and the variables in the given problem are both x^3.
2007-09-30 20:49:06
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answer #5
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answered by edith p 3
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agree with PETE. Charlie is wrong because you only add exponents when you MULTIPLY. X^3 TIMES X^3=x^6
X^3 PLUS X^3=2X^3
2007-09-30 20:48:48
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answer #6
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answered by Mike 7
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neither. x^3+x^3=2x^3
2007-09-30 20:46:24
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answer #7
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answered by Anonymous
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x^6 b/c they have the same base variable/number, so you add the exponents.
2007-09-30 20:45:44
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answer #8
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answered by Anonymous
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