How do you graph x=y squared?

Question

how do you graph x=y squared-can someone do it on paint or something or explain or provide a link?
is y a function of x?

Answer 1

x = y ²

Plot some points to obtain curve:-

y |- 3" - 2" - 1"""0"" 1"" 2"""3
x |"9""""4""""1"""0""""1""4"""9

Curve will be symmetrical about x axis with vertex at origin.
Curve lies to right of y axis.

Answer 2

x = y^2 can be graphed as x = +/- sqrt ( x )

this is a sideways parabola

to imagine it graphically:

take the graph y=x^2 (this is a parabola going through the origin)

now take that graph and rotate it so that, instead of both lines being around the positive y-axis, they are around the positive x-axis.

this is my best attempt at explaining it without showing the graph

hope it helps,
anthony

Answer 3

start with a chart, x and y^2. x is the indepenent variable. so in this chart, you'll have x equal a bunch of numbers 1 thru 5 and so on. you'll then need to find what y^2 equals to each x variable.

x | y^2
1 1
2 4
3 9
4 16
5 25

You then plot these number on a coordinate chart. You'll plot points (1,1); (2,4); (3,9); (4,16); & (5,25). What you end up getting is half a parabola (with these numbers). But if you throw some negative numbers for x, you will end up plotting a parabola.

Answer 4

stupid *** that answered it as a u going up!! what a retard. ok look
since it is x=y^2 and not y=x^2 it goes to the side. the open end is going to the right. the vertex is at (0,0). like this <, but with a curve, not straight lines. if it was y=x^2, then it would be a u with the open end going up and the vertex at (0,0)

Answer 5

My attempt at answering it will be it looks like the letter C, with vertex at the origin, and axis of symmetry the x-axis instead of the y axis.

EDIT: Very nice picture by steven above.

Answer 6

here are a few sample cordinates:

(25,5)
(16,4)
(9,3)
(4,2)
(1,1)
(0,0)
(1,-1)
(4,-2)
(9,-3)
(16,-4)
(25,-5)

and your graph will look lie a "C"

sorry ... could quite figure out how to grph it and idplay it here, but you should get the idea.

Answer 7

it would be a parabola, as x=y^2 is a quadratic function.
it would look like a u, opening upward, with the bottom at (0,0)

Answer 8

http://andrew06035.googlepages.com/Graph.gif

I'm not going to get into all that math stuff, because I won't allow myself to think too much at 8:50 on a Sunday night.

Answer 9

+----------------X-------------y=4
+---------X--------------------y=3
+----X-------------------------y=2
+-X----------------------------y=1
+X-----------------------------y=0
+-X----------------------------y=-1
+----X-------------------------y=-2
+---------X--------------------y=-3
+----------------X-------------y=-4

Answer 10

( I )
( I )
( I )
___I___
I
I
I