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have been reduced:
Cl2+I2 to form I2 + Cl-
WO2+H2 to form W + H2O
Ca + H2O to form H2 + Ca(OH)2
4Al + 3O2 to form 2Al2O3

2007-09-30 13:33:03 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Cl2 + 2I- ----> 2Cl- + I2 (Cl2 is reduced)
WO2 + 2H2 ----> W + 2H2O (WO2 is reduced)
Ca + 2H2O ----> Ca(OH)2 + H2 (H2O is reduced)
4Al + 3O2 ---> 2Al2O3 (O2 is reduced)

2007-10-01 08:13:53 · answer #1 · answered by Gervald F 7 · 0 0

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