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49x^2 + 9 = 42x

&

6x = 19x + 25 / x+1 <--(fraction)

2007-09-30 11:53:14 · 1 answers · asked by plplz 1 in Science & Mathematics Mathematics

1 answers

49x^2 + 9 = 42x
49x^2-42x+9 =0
(7x-3)^2 = 0
x = 3/7

6x = 19x + 25 /(x+1)
-13x = 25/(x+1)
-13x^2 -13x = 25
13x^2+13x+25 = 0
x =[-13 +/- sqrt(13^2-4(13)(25))]/(2*13)
x = [-13 +/- i*sqrt(1131)]/26
x = -.5 +/- (1/26)i sqrt(1131)

2007-09-30 12:10:39 · answer #1 · answered by ironduke8159 7 · 0 0

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