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2007-09-30 11:25:16 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

you are getting different answers because it depends on what you mean by "inverse"

2007-09-30 11:42:08 · answer #1 · answered by Paladin 7 · 0 0

You need to specify the order in which the exponents are being applied.

2^(6^x) and (2^6)^x are both possibilities, the way you've written it, and they are very different quantities.

The inverse of 2^(6^x) is
= 1 / (2^(6^x))
= (2^(6^x))^(-1)
= 2^(-6^x)

The inversion of (2^6)^x is
= 1 / ((2^6)^x)
= 1 / (64^x)
= (64^x)^(-1)
= 64^(-x)

2007-09-30 18:29:54 · answer #2 · answered by lithiumdeuteride 7 · 0 0

y =(2)^(6)^x = 2^(6x)
ln(y ) = 6x ln(2)
x = ln(y)/(6ln(2))
y = ln(x)/(6ln(2))

2007-09-30 18:36:28 · answer #3 · answered by ironduke8159 7 · 0 0

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