can someone answer this math question?

Question

x2-8x+15
(x to the power of two)
i no its really basic but i have forgotten how to do it
can u please do it step by step
thankuX

Answer 1

The only thing you can do is factor
(x-5)(x-3)

Answer 2

You can factor this to (x - 5)(x - 3) so if you are looking to solve this:

x^2 + 8x + 15 = 0

the answers are x = 5 and x = 3.

Answer 3

you factor this out, so (x-3)(x-5)
in this, -3-5=-8, and -3*-5=15
you set this equal to zero, so
(x-3)(x-5)=0, and therefore (x-3)=0 and (x-5)=0
if (x-3)=0, then x=3
and if (x-5)=0, then x=5
your answers are 3 and 5

now you check it

x^2-8x+15
(3)^2-8(3)+15
9-24+15=0, so this works

x^2-8x+15
(5)^2-8(5)+15
25-40+15=0, so this works

x=5 and x=3

Answer 4

x2-8x+15=0

You have to factor this equation so it takes the form:
(x+a)(x+b)=0
then the two answers will be x=-a and x=-b

for your problem x2-8x+15
what two a, and b will multiply to +15, and add to -8?
possibilities (1,15) (-1,-15) (3,5) (-3,-5)

Of all the possibilities only (-3,-5) both multiply to 15 and add to -8.

so your equation factors to
(x-3)(x-5)=0
giving x=3 and x=5 as answers

Answer 5

x^2 - 8x + 15? I'm assumine x^2-8x+15 = 0?

(x + Y) * (x + Z) = x^2 - 8x + 15
well... Yx and Zx have to equal -8
Y * Z have to equal 15

Y = -3
Z = -5

-3 * -5 = 15
-3x + -5x = -8

Answer 6

Use the quadratic formula (look it up if you don't know) or factor the equation getting the answer:

(x-5) ( x-3) = 0

Set each set of parathensis to 0 and solve resulting in
x = 3,5

Answer 7

What is your question? Do you want to factor the expression? Do you want to solve x^2 - 8x + 15 = 0? Do you want to graph y = x^2 - 8x + 15? Please clarify.

Answer 8

The reason you are having trouble may be that you don't have a whole solveable problem there!

Did you mean "x^2 - 8x + 15 = 0", maybe?

Answer 9

Yea and for me interestingly on non-math questions too bcs i exploit msn language now and back too. And it takes removed from ur self belief. Lol, I have been provided that punctation errors once I wrote this reaction.

Answer 10

you have to factor it.

(x-5)(x-3)

Then set each one to zero and solve.

x-5 = 0.... x=5
x-3 = 0.... x=3