A ball thrown vertically upward is caught by the thrower after 4.0 s
1. find the initial velocity of the ball (upwards)
2. find the maximum height it reaches
2007-09-30 08:41:48 · 3 answers · asked by roofchelsea 1 in Science & Mathematics ➔ Physics
Initial velocity = final velocity
Time up = time down=4/2=4sec
V=V0 - gt
V- velocity
V0 - initial velocity
t - time to travel (one way)
g - acceleration due to gravity
V= 0 at the very top
V0=gt
V=9.81 x 2= 19.62 m/s
h= 0.5gt^2
h= 0.5 x 9.81 x (2)^2=19.62 m
2007-09-30 14:47:50 · answer #1 · answered by Edward 7 · 1⤊ 0⤋
Use the kinematic equation d = Vi t + a million/2at² Look at how the ball is falling within the vertical course. We wish to understand how lengthy it takes for it to fall vertically 10m. The ball is thrown horizontally, so there can be no preliminary vertical speed. It is being improved through gravity. d = (zero)t + a million/2gt² d = a million/2gt² Now plug for your values and clear up for t: 10m = (a million/two)(10m/s²)t² t² = 2s² t = ?(2s²) = a million.41s
2016-09-05 12:38:45 · answer #2 · answered by ? 4 · 0⤊ 0⤋
not enough info
2007-09-30 08:49:10 · answer #3 · answered by Awan 2 · 1⤊ 1⤋