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i have to push a 100kg box up a 20degree ramp into the truck. (coeff of static friction)=0.9 and coeff of kinetic friction =0.6. my largest pushing force is 1000N. will i be able to push the box up the truck without assistance if i started running?If i stop on the ramp, will i be able to move the box again??

2007-09-30 06:49:56 · 1 answers · asked by berry 1 in Science & Mathematics Physics

1 answers

Ft=Fd+f
Fd=mgsin(20)
f=umgcos(20)
Ft=mg(sin(20) + ucos(20))
so
Ft for static case
Ft= 100 x 9.81 (sin(20) + 0.9cos(20))=
Ft=1165N ( it would not even budge)

Ft for kinetic case
Ft= 100 x 9.81 (sin(20) + 0.6cos(20))
Ft=887N
If you could overcome the initial 1165N you could get the box into the truck.

2007-10-02 04:42:27 · answer #1 · answered by Edward 7 · 0 0

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