A pumped-storage reservoir sits 155 m above its generating station and holds 8.5 *10^9 kg of water. The power plant generates 320 MW of electric power while draining the reservoir over an 8.5 hour period. What fraction of the initial potential energy is lost to nonconservative forces (i.e., does not emerge as electricity)?
2007-09-30 05:04:39 · 2 answers · asked by dsgdh 2 in Science & Mathematics ➔ Physics
Since dimensions of the tank are not given, I assume the head is constant. Potential energy PE = mgh. Output energy E = 8.5*3600*3.2E8. Fraction of energy lost η = (PE-E)/PE.
2007-10-01 03:32:44 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
the ability ability PE = 8.5*10^9 *9.8*one hundred fifty five Joule = The ability generated with the help of the ability plant is 350*10^6*8 *3600 joule the adaptation is two.8315*10^12 joule ability misplaced to nonconservative forces
2017-01-02 20:17:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋