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A 1500 kg car is moving with a speed of 25 m/s. How much work is required to stop the car?

Thanks

2007-09-30 03:26:02 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

W = (0.5)*mf*vf^2 - (0.5)*mi*vi^2
Where f means final and the i means initial. In this case, vf is going to be zero, so then:
W = -(0.5)*mi*vi^2
W = -(0.5)*1500*(25)^2 = -468750 J

The negative sign indicates that the work is being done against the motion of the car.

2007-09-30 03:41:37 · answer #1 · answered by kylekanos 2 · 0 0

you must reduce its kinetic energy to 0
KE= 1/2mv^2 = 1/2*1500*625= 468,759 Joules

2007-09-30 10:37:20 · answer #2 · answered by santmann2002 7 · 0 0

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