Ok so im in pre calc 2 and have a test in a few day and cant figure this type of problem out!!!! My teach is really not alot of help.
it says find the exact value of each expression, with out using calculator
i under stand this problem...
(sin^ -1) (1) thats suppost to be read as inverse sin of 1. but i cant really type it right on here. but all you do is go to Sin= 1 on the unit circle and thats = to π / 2 (thats pi over 2)
i also get all the other ones like that but...
how do i do this one...
(sin^-1)((cos)(2π / 3)) i know the answer is -π/6 but how do i get that? Please explain!!!!!!! thank you so much
also other ones i cant solve but is the same way
(cos^-1)((tan)(3π/4))
Tan^-1 ( tan (7π/4))
Cos^-1 (cos(7π/6))
thank you for all the help you may provide! if anything simplify your explaination as much as you can lol thank you again have a great day
2007-09-29 17:17:08 · 2 answers · asked by It can only be me! 1 in Science & Mathematics ➔ Mathematics
read arcsin x = y as x = the angle y whose value is x
cos (2π / 3) = - 1/2
arcsin (-1/2) = 11π / 6 or -π / 6
tan((3π / 4) = -1
cos(-1) = π
arctan(tan(x)) = x, so arctan(tan(7π / 4)) = 7π /4
arccos(cos(x)) = x, arccos(cos((7π / 6)) = 7π / 6
2007-09-29 17:32:21 · answer #1 · answered by norman 7 · 0⤊ 0⤋
looks like your sin^-1, etc is the inverse function. That is, arcsin, etc.
2007-09-30 00:28:04 · answer #2 · answered by hahagoodguy 2 · 0⤊ 0⤋