Rectangle A has dimensions 4 in x 8 in. Rec. B has dim. 5 in x 7 in.?

Question

Which statement is true? Their perimeters are equal?
Their areas are equal? Or both?

Answer 1

rectangle"""perimeter"""area
A"""""""""""""24""""""""""""32
B"""""""""""""24""""""""""""35
Perimeters are equal

Answer 2

Perimeter = 2(sum of the dimensions)

perimeter of A = 2(l+w) = 2(4+8) =24 in

perimeter of B = 2(l+w) = 2(5+7) = 24 in

Area = product of dimensions

area of A = 4*8 = 32 sq.in

Area of B = 5*7 = 35 sq. in

so perimeters are equal

Answer 3

Perimeter of a rectangle is 2(l+b)
So, for Rect. A
perimeter= 2(4+8)= 2(12)=24 in
For rectangle B,
Perimeter= 2(5+7)= 2(12)= 24 in
So their perimeters are equal.
Let's check their areas
Area of a rectangle= l*b
Area of Rectangle A= 4*8= 32 sq in
Area of Rectangle B= 7*5= 35sq in

So their perimeters are equal.

Answer 4

Equation for perimeter of a rectangle is p= 2(l+w)

A: P= 2(4+8)
=2(12)
P= 24

B: P=2(7+5)
= 2(12)
P=24

The statement is true. Both perimeters of rectangle A and rectangle B is 24 units.

Answer 5

Perimeter = 2(Length + Width)
Area = Length x Width

You notice that half perimeter are the same
4 + 8 = 12
5 + 7 = 12

Whereas the areas are not the same
4 x 8 = 32
5 x 7 = 35

So, the statement, "The perimeters are equal" is true
The statement, "Their areas are equal" is false.

Answer 6

WHAT???
You honestly don't know how to calculate this???
Their perimeters are equal (both of them are 24") but the area of the 4 X 8 is 32 sq inches and the other one is 35 sq in.

Doug

Answer 7

areas are not the same.
The area of the 4x8 rectangle is 32 sq in
the area of the 5x7 rectangle is 35 sq in

perimeters are the same. both are 24 in

Answer 8

areas not equal B= 35in A= 28in
perimeters are equal

Answer 9

4x8=32 in squared
5x7=35 in squared
areas are not equal
4x2+8x2=24
5x2+7x2=24
perimeters are eual

Answer 10

Area
4in x 8in = 32in²

5in x 7in = 35in²

Perimeter
4in(2) + 8in(2)
= 8in + 16in
= 24in

5in(2) + 7in(2)
= 10in + 14in
= 24in
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Area
A ≠ B

Perimeter
A = B