find the derivative of the function? y=1/x-2?

2 ⤊

find the derivative of the function? y=1/x-2?

2007-09-29 16:26:55 · 3 answers · asked by nala 1 in Science & Mathematics ➔ Mathematics

3 answers

use the quotient rule
y'= [(x-2)d/dx 1 - 1 d/dx (x-2)]/(x-2)^2
y' = [0-1(1)]/(x-2)^2
y' = -1/(x-2)^2

2007-09-29 17:05:05 · answer #1 · answered by Anonymous · 2⤊ 1⤋

This follows the power rule. Think of it as (x-2)^-1.

2007-09-29 16:30:59 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋

Did you mean 1/(x) - 2
y = 1/x - 2, which is also
y = x^-1 - 2
y' = -x^-2, which is also
y' = -1/x^2

Or if you mean 1/(x-2)
y = 1/(x-2), which is also
y = (x-2)^-1
y' = (1) * -(x-2)^-2, which is also
y' = -1/(x-2)^2

2007-09-29 16:31:18 · answer #3 · answered by Matiego 3 · 0⤊ 0⤋