solve by linear combination
2007-09-29 15:13:42 · 8 answers · asked by MarieKatie 1 in Science & Mathematics ➔ Mathematics
1/2x=4y
x=8y
x=8y
and...
5y-x=-3
-x=-3-5y
x=3+5y
set those equal to each other and...
8y=3+5y
3y=3
y=1
Substitute
x=8y
x=8(1)
x=8
so...
x=8
y=1
2007-09-29 15:20:52 · answer #1 · answered by Snipe_AT 2 · 0⤊ 0⤋
solve for x in the first equation
x/2 = 4y
x = 8y
plug this in for x in the second equation
5y - 8y = -3
-3y = -3
y = 1
then plug y into either equation and find x
x/2 = 4y
x/2 = 4
x = 8
2007-09-29 15:22:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Reading this as:-
(1/2) x = 4y
x = 8y
5y - 8y = - 3
- 3y = - 3
y = 1
x = 8
2007-09-29 22:16:32 · answer #3 · answered by Como 7 · 0⤊ 0⤋
x=5y+3...1/2(5y+3)=4y...40y^2+24y-1=0...this gives u a hint?
2007-09-29 15:26:59 · answer #4 · answered by Anonymous · 0⤊ 0⤋
1/2x = 4y
x = 8y
5y - x = -3
5y - (8y) = -3
-3y = -3
y = 1
x = 8(1)
x = 8
2007-09-29 15:21:44 · answer #5 · answered by Matiego 3 · 0⤊ 0⤋
1/2x=4x => x=8y
5y-8y=-3 => -3y=-3 => y=1
x=8(1)=8
(x,y) = (8,1)
2007-09-29 15:22:02 · answer #6 · answered by Anonymous · 0⤊ 0⤋
The first equation is ambiguous. Do you mean
1/(2x)=4y or 1/(2x)=4y
2007-09-29 15:22:09 · answer #7 · answered by vcs7578 5 · 0⤊ 0⤋
y = 1
x = 8
I think...it's been a while since I've taken algebra
2007-09-29 15:21:07 · answer #8 · answered by Chris B 2 · 0⤊ 0⤋