Can someone explain this to me real well? I dont understand this?

Question

Parallel to 2x+2y=8 and through (-1,-4)

Answer 1

2x + 2y = 8
x + y = 4
y = - x + 4----(m = - 1)
y - ( - 4 ) = (-1) [ x - ( -1 ) ]
y + 4 = (-1) (x + 1)
y + 4 = - x - 1
y = - x - 5

Answer 2

Rewrite the equation of the line in slope-intercept form or y=mx + b

where m = slope and b is the y-intercept

To do that divide the whole equation by 2 and transpose the term with variable x to the right side of the eqn.

2x + 2y = 8

Divide by 2:

x + y = 4

y = - x + 4

Compare the above equation with y = mx + b. It is obvious that m = -1 and b = 4.

Parallel lines have the same values for the slope. This means your new line also has a slope of -1.

Make a new line equation with slope, m = -1

y = - x + b'

All we need now is the value of b' or y-intercept of the new line. To do that substitute x = -1, and y = -4 into the equation:

-4 = - (-1) + b'

-4 = 1 + b'

solve for b'

b' = -4 -1 = -5

The equation for a line parallel to 2x + 2y = 8 that passes through (-1,-4) is

y = - x - 5

Answer 3

I suppose you're looking for the equation parallel to 2x+2y=4 and through the point (-1, -4).
2x+2y=4
x+y =2
y = -x +2 so m= -1 ( the slope)

So, we are looking for an equation with a slope of -1 and passes through the point (-1, -4).

All equations with slope -1 satisfies the equation y=-x+b

Substitute the point (-1, -4) into y=-x+b gives b=-5.

So, the required equation is
y= -x -5

Answer 4

You need to create a line that is parallel to the line created by the equation 2x+2y=8, that also passed through the point (-1,-4) on the coordinate. How you can figure that out is to figure out the slope of the equation "2x+2y=8", because your new line has to have the same slope as "2x+2y=8". Think of slope as the angle the line goes. In case you don't already know, parallel lines are two lines of equal distance from each other all the way up and down.

To find out the slope of the equation, you need to rewrite the equation 2x+2y=8 in the format of y=mx+b. The "m" in y=mx+b is the slope. So 2x+2y=8 will be rewritten as y=-x+4. If you're wondering how I turned 2x+2y=8 into y=-x+4, here's why:

2x+2y=8 [this is the original]

2y=8-2x [subtract 2x from one side of the equation to get it to the other side]

2y=-2x+8 [rearrange the equation so x would come first on the right side]

y=-x+4 [divide everything by 2 in order to get rid of the 2 infront of the y]

Your slope (which is the angle of the line) is "m" in the equation y=mx+b. Before the x in the equation you get a - (negative sign), so that would indicate that the slope is -1 (negative one).

Now you need to draw a line on a coordinate that passes through the point (-1,-4) with a slope of -1. How you do that is, first you need to locate (-1,-4) on the coordinate. Then, from that point, you go down one square from the point, and move to the right one point. Why? Because a negative slope means the line descends (go down) from left to right, while a positive slope rises from left to right. Usually, if it's a fractional slope like 2/3, you would go up twice, and move to the right three times. However, when you get a whole number, you'd turn that into a fraction. 3 is 3/1, so -1 is -1/1. The numerator (fractional number on top) of the fraction tells you how many steps to move upwards (if positive) or downwards (if negative) the coordinate, and the denominator (fractional number on the bottom) tells you how many units to move to the left.

It's one of those things that's kinda confusing to explain through words... I'm not sure whether you have to write a formula of a line parallel to 2x+2y=8 that passes through (-1,-4), or graph the equation of such line. I just taught you how to graph it. As to how to find the formula of such line, you gotta substitute the slope and the points into the point slope formula... which you have to look up online because I can't type it out on this keyboard. I think I gave you more than sufficient details...lol

Answer 5

There is a formula for writing an equation for straight lines if you know the line goes through a certain point and it has a certain slope.

y=m(x-h)+k
This is called the point-slope formula.

m is the slope, and it goes through the point (h,k).

In this case, you're given the point (-1,-4), so that's your h and your k. Now all you need is the slope m.

We want our new line to be parallel to the line 2x+2y=8. Parallel lines have the same slope, so we want our line to have the same slope as that one. What's the slope of 2x+2y=8? The easiest way to tell is to put it into y=mx+b form and the m is your slope. So solve for y and look at the coefficient of x on the other side. Now you have m.

Put h and k and m in to the point-slope formula and now all you have to do is simplify the equation. There are two popular choices of how to leave your answer. One is the slope-intercept form y=mx+b. The other is called standard form, ax+by=c.

For example, if you get y=3(x-2)+5 you could write
y=3x-6+5
y=3x-1 <--- slope-intercept form
or
0=3x-1+y
1=3x+y
3x+y=1 <---- standard form

Answer 6

A line parallel to the line 2x+2y=8 which passes through the point
(-1, -4). And the equation of that line would be
2x + 2y = -10

Doug

Answer 7

Two lines are parallel if they have the same slopes. Here's how to solve this step by step...

1.) Put the equation in standard (y = mx + b) form to determine the slope. To do this, divide both sides by 2. This gives x + y = 4. Subtract the x to the right hand side. This gives an equation of y = -x + 4. So this implies that the slope is -1.

2.) Use the formula for point slope form to find the equation for the second line. That's y - y1 = m(x - x1). We know m has to be -1, so let's plug in the slope, x1, and y1.

y - (-4) = (-1)(x - (-1))
y + 4 = -(x + 4)
y + 4 = -x - 4
y = -x - 4 - 4
y = -x - 8

3.) So the second equation is y = -x - 8.

Answer 8

it is a graphing question.

2x + 2y = 8
subtract 2x from both sides
2y = -2x + 8
divide everything by 2
y = -x + 4
the (-1, -4) is the y intercept or where the line intesects on the y axis
start at that piont and go up one and to the left one make a point. do this over and over
then start at that point again and go down one and to the right one and make a point. do this over and over.
connect the points to make a line
that should be your answer

o and the graph should have 4 quadrants
toward the bottom and toward the left are negative
toward the right and toward the top are positive.
quadrant 1 is the top right
quadrant 2 is the top left
quadrant 3 is the bottom left quadrant
4 is the bottom right

Answer 9

First find the slope of the line..so change it into the normal line formula y=mx+b. b is the y-intercept, and m is the slope
2y=8-2x
y=(8-2x)/2

y= 2(4-x)/2

Cancel out the 2's..you get y=4-x
The slope of the line is -1. So now, to make the equation for the new line, we know the y intercept is -4. So simply insert this into the equation.
y= -x-4 is your answer

Answer 10

Change it to slope intercept form like y= -x+4
Parallel lines means that the slopes which is -1 and the equation to the other line also has the same slope of -1
then from (-1,-4) follow the slope of the line or put in into the Eq.
hint : the equation to the other line is y= -1x -5

Answer 11

well first of all "parallel to" means to have the same gradient so firstly you need to find the gradient of the given equation

so 2y = 8 - 2x
then y=(8 - 2x)/2
simplify y= 2- x

so your gradient is the number infront of the x variable
i hear you saying that there is no number infront of the x variable but there is

the gradient is -1

so now you have everything you need you just need to find the equation of the line in the form of y=mx+c where m is your gradient and c is your constant

so far you have the m value

y= -1x +c
you were given two points on the line so substitue them into the equation you have formed to find c

so y= -4 nd x= -1

-4 = -1*(-1) +c
- 4 = 1 +c
-4 -1=c
-5 =c

now you have your equation

y= - x - 5