I've tried everything. Please pity me!?

Question

Ok this physics prob has me stuck for the past 2 hours. please help me solve it.
object was thrown at an initial vel of 7m/s from 92 m above ground. Another object was thrown up at inital vel of 29 m/s. if acc due to gravity is 9.8.
Then at what height will the objects pass each other.
I have gone crazy trying to solve this so any answers or help will be appreciated.
Thanks and first correct answer gets 10 points.

Answer 1

Wow, that was confusing. Took me about half an hour. The answer is 42.11m, rounded of course. The confusing part of this problem is that the objects are going in opposite directions. Just separate this into 2 cases then. I'll call the object in the air "object 1" and the one on the ground "object 2". "Positive" displacement for object 2 would be up and down for object 1. You start by using the equation d=vit + .5at^2. Since the problem is asking for the height when they meet each other, you can alter the equation this way : 92 - d = vit + .5at^2. The left side is equal to the height they meet and the right side is will be object 2's displacement Then you substitute that d and get 92 - (vit + .5at^2) = vit + .5at^2. The left side using object 1's constants and the right side being object 2's constants. Make sure you use negative acceleration on the right side because the object is acting against gravity. Substitute the right numbers in, and you get the time at which they meet each other. Then you use the equation d = vit + .5at^2 again (since you know the time now) to get the displacement of object 2 when it is in the air. To check, you do the same for object 1 but subtract that displacement from 92 since it is going down.
Hope that wasn't too confusing. It's hard to explain equations and concepts with just text.

Answer 2

set the displacement formulas equal to each other:
s(upper) = s(lower)
s(1 zero) + v(1 zero)t + (1/2)at^2 = s(2 zero) + v(2 zero)t + (1/2)at^2
92 + 7t = 29t
92 = 22t
t = 4.1818s
Plug back into the lower:
s = 29t - 4.9t^2
s = 29(4.1818) - 4.9(4.1818)^2
s = 35.584m