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3 answers

It's not necessarily the case that all H atoms would be attacked equally by the halogen... The reason that free radical halogenation of an organic compound yields a mixture of compounds is simply because the H atoms in the original compound are NOT all equivalent to each other. Replacing, say, an H atom on the end of a chain (a CH3 group) with a Cl atom gives a different compound than replacing a H in a CH2 group in the middle of a chain. Since the halogen can normally access many different H atoms, there is usually more than one possible product of the reaction.

2007-09-29 09:36:40 · answer #1 · answered by mnrlboy 5 · 0 0

Free Radical Halogenation

2016-10-02 03:37:23 · answer #2 · answered by porada 4 · 0 0

Because all the H atoms of the alkane are equally likely to be attacked by the chlorine radicals.

2007-09-29 09:12:27 · answer #3 · answered by Gervald F 7 · 1 0

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