solve, 3/(x-1)=6/(x+2)?

Answer 1

3/(x-1)=6/(x+2) Multiply both sides by (x-1)
3 = 6(x-1)/(x+2) Multiply both sides by (x+2)
3(x+2) = 6(x-1) Do the indicated multiplication
3x+6 = 6x-6 Subtract 3x from both sides
6 = 6x - 3x - 6 Add 6 to both sides
12 = 3x Divide by 3
4 = x

Doug

Answer 2

First of all, find the points where this equation doesn't exist, this is where x-1 = 0 and/or x +2 = -2

If a = b => 1/b = 1/a unless either b or a are 0. But neither 3 nor 6 are 0 so, let's go on.

So, (x-1)/3 = (x+2)/6

Multiply by 6 and you will get:

2(x-1) = x+2

Which leads you to a pretty easy first grad equation

Ilusion

Answer 3

your two denominators are different so you have to find the least common denominator by multiplying them. so you're common denominator is (x-1)(x+2)

having that, you multiply everything by your common denominator and you get

(x-1)(x+2) [ 3/(x-1) = 6/(x+2)]

when you multiply,

[3(x-1)(x+2)]/(x-1) = [6(x-1)(x+2)]/(x+2)

your (x-1) cancels out on the right side, and your (x+2) cancels out on the left, so you're left with

3(x+2) = 6(x-1)

simplify

3x + 6 = 6x - 6

then solve for x

3x + 6 = 6x - 6
-6x -6x
-3x + 6 = -6
-6 -6
-3x = -12
divide by -3
you get:

x = 4

Answer 4

Use cross division:

3(x+2) = 6(x-1)
3x+6 = 6x -6
-3x = -12
x = 4

Answer 5

4

3*(x+2) = 6*(x-1)

3x + 6 = 6x-6

x = 4

Answer 6

The first answer is correct. However it is not cross division; rather, it is cross multiplication.

Answer 7

x=4

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