How is 3(L^1/3) times (24-L)^1/3 equal to L(24-L) ?
2007-09-29 07:46:34 · 5 answers · asked by John L 2 in Science & Mathematics ➔ Mathematics
3(L^1/3) times (24-L)^1/3 equal to L(24-L)
= 3(L(24-L)^1/3
Your statement is incorrect.
Let L= 8
Then 3(L^1/3) = 6, and
(24-L)^1/3 = (24-8)^1/3 = 2*2^1/3
So their product is 12*2^1/3
But L(24-L) = 8*16 =128
12*2^1/3 not = 128
I think you are confusing logx^n = nlogx with this somehow.
2007-09-29 08:30:45 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
when u said simple i thought u meant 3(5+9)=? but srry don't know
2007-09-29 07:50:38 · answer #2 · answered by iLoveBeiber 1 · 0⤊ 1⤋
Yeah, very simple, haha.
I dont know. Those signs confuse me. Try to correct it.
2007-09-29 08:04:09 · answer #3 · answered by korrupted... 2 · 0⤊ 0⤋
thats crazy im in pre algebra in 7th grade and we never talked about that
2007-09-29 08:11:38 · answer #4 · answered by Anonymous · 0⤊ 0⤋
simple?
jk
no idea!!!!
ask the teacher
2007-09-29 08:01:31 · answer #5 · answered by carr 3 · 0⤊ 0⤋