A student measures 1.7296 g of a mixture of sand and sodium carbonate, which is later determined to be 24.29% sand.
What mass of Na2CO3 was in the original mixture?
How many moles of Na2CO3 were in the original mixture?
2007-09-29 06:23:25 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
24.29 : 100 = x : 1.7296
x = 0.4201 g of sand
Mass Na2CO3 = 1.7296 - 0.4201 = 1.3095 g
Molar mass = 105.99 g/mol
1.3095 g /105.99 g/mol = 0.01235 mol Na2CO3
2007-09-29 08:36:38 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋
1. work out 100 - 24.29
2. divide by 100 and multiply this by 1.7296 (that's the mass of Na2CO3)
3. divide the mass by 106 to get the moles
2007-09-29 06:29:45 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
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2017-01-02 19:48:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋