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Person throws .15 kg baseball at speed of 42 m/s. Initial angle is 20 degrees. What is KE of ball at highest point?

2007-09-29 06:08:09 · 1 answers · asked by ひいらぎ 5 in Science & Mathematics Physics

1 answers

At the highest point the vertical component is zero and the horizontal component is 42cos(20) = 39.46 m/s so the KE is
(1/2)mv² = (1/2).15*39.46²=116.78 J

Doug

2007-09-29 06:36:12 · answer #1 · answered by doug_donaghue 7 · 0 0

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