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hello i came across a question in my physics homework that i will really appreciate help with. Here it is:

at 3:00 p.m. a truck traveling on a winding highway has a velocity of 82.0 km/h [N 38.2 E] ; at 3:15 p.m., it has a velocity of 82.0 km/h [E 12.7 S]. Assuming that +x is easy and +y is north, determine the x- and y-components of the average acceleration during this time interval.

the answer at the back of the book:
a av,x = 9.0 x 10^-3 m/s^2
a av,y = -2.5 x 10^-2 m/s^2

thanks a lot for anyhelp!

2007-09-29 05:32:07 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Break both velocities into x and y components.

Find the change, delta vx, in the x velocity. This took place over 15*60 seconds. The x component of the acceleration is given by
ax = delta vx/time.

Repeat in y axis.

2007-09-29 06:43:18 · answer #1 · answered by sojsail 7 · 0 0

those are all graphical representations, and are superb. the objective of the diagram is to help visualize importance and process each and every stress. All 3 do this, nevertheless 2 and 3 are maximum suitable to apply for the trig to % the forces. even though, no count the way you draw it, the forces act on the factor indicated in a million. hence, a million is maximum suited. The horizontal element yields no torque, because of the fact the 2d arm is 0. 2 and 3 are deceptive, because of the fact they may well be considered to teach one element performing in the incorrect place.

2016-10-20 07:33:26 · answer #2 · answered by Anonymous · 0 0

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