On a soccer team of 22 players a starting lineup of 14 players will be chosen. 1 of 2 keepers is chosen 4of 6 defenders are chosen. 4of 8 halfs are chosen . 2of 6 strikers are chosen .The 11 players starting lineup can be created in ____?
Four of eleven numbered balls are withdrawn from a container in sequence without replacement . What is the proability that the 3rd number is greater than a 7 and the 4th number less than a three expressed to the nearest tenth of a percent? Assume that the ball numbers begins at 1 and end at 11 and no numbers are repeating.
Is anyone show the steps or what formulas should be used ?
thx.
2007-09-29 05:09:56 · 1 answers · asked by Try L 1 in Science & Mathematics ➔ Mathematics
It's a little unclear. Is the starting lineup 14 or 11 players?
It appears that there are 2C1 ways to select 1 keeper,
6C4 ways to select 4 defenders,
8C4 ways to select 4 halfs, and
6C2 ways to select 2 strikers
So the total is the product of these 4 Combibatios.
The 3rd number has to be an 8 or a 9. The probability of this is 2/11. The 4th number must be a 2 or a 1. The probability of this is 2/10 = 1/5. Total probability is 2/55.
2007-09-29 05:38:23 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋