Help!!!! please!!!!!! please!!!! 10 poitns!?

Question

four students reach into a bag of marbles. Dakota grabs 1/3 of the marbles, Martin grabs 1/3, and Dave grabs 1/6. if Ryan get the remaining 6 marbles, how many marbles were originally in the bag?


if d=axbxc, where a,b and c are three different prime factors, incluiding 1 and d, does d have?



a group of tourist paid a total of $240 for admission to a museum exhibit. If the admission price for each adult was $10 and the admission price for each child was $5, how many adults were admitted to the exhibit?

thanks!!!! i need help!!!

in the last problem are 30 tourists!

Answer 1

1. The first 3 students grab 5/6 of the marbles.
So 1/6 of the total is left. Thus 1/6 x = 6
x = 36 marbles.

2. I'll assume that you are asking how many factors
does d have. The answer is 8. We can list them as
1 a b c ab ac bc and abc = d.

3. This is a Diophantine problem.
Let x be the number of children and y the number of
adults.
Then 5x + 10y = 240
or
x + 2y = 48.
We want to solve this in nonnegative integers.
We see that y can be any number from 0 to 24
and x is any even number between 0 and 48.
There are 25 solutions in all.
If you add the condition that there were 30 tourists
then x + y = 30
and x + 2y = 48
So y = 18, the number of adults
x = 12, the number of children.

Answer 2

For the first one, just add the fractions together first, 1/3 + 1/3 + 1/6...Which equals 5/6, so if the remainder is 1/6 of the total, than you just multiply it by 6 to get the original amount...i.e. 6*6

For the second one, you have to type the whole problem to get any help on that one....what you have isn't enough to go on.

For the third, 30 tourists, eh? Well, you know they aren't all adults, because that would make your total $300....and you know they weren't all kids, because that would make your total $150....

So, write it out. Worse case scenario, if you don't know the equations to use, sometimes writing it out is really simple, too.

In this case, you know that 24 adults would be $240, and 23 adults would be $230, so you could add 2 kids, and have 25 people to make $240...keep going like that until you find the answer...
22 adults=4 kids
21 adults=6 kids
20 adults=8 kids
19 adults=10 kids
18 adults=12 kids

So there were 18 adults and 12 kids.

Answer 3

1. You've used up 5/6 of the marbles already, so 6 marbles is 1/6 of the marbles, 6*6=36 marbles to begin with.

2. Does d have what? You haven't finished your sentence.

3. Again, it's impossible to say. There could have been anywhere from 0 to 24 adults. As in question 2, you seem to be missing part of the question.

Answer 4

1. Let the number of marbles is x.
Therefore, total number of marbles grabbed is
x/3 + x/3 + x/6 = 5x/6
Remaining marbles are x/6.
Therefore,
x/6 = 6
x = 36
Total marbles = 36

2. Question is incomplete.

3. let number of adults is x and the number of children is y.
Therefore,

x + y = 30 and
10x + 5y = 240

Therefore,
x + y = 30
2x + y = 48

Therefore,
x = adults = 18
y = children = 12

Answer 5

assuming that these are three problems

1. 1/3 + 1/3 + 1/6 = 5/6 so
6 = 1/6 so
36 is the total marbles

2. i'm assuming that you mean't d = ax*bx*c, and does d have what???

3. 240 = total
it could be anything from zero to 24 , you need to say how many people went in total.

Answer 6

Try it by yourself

Answer 7

Hey do your own homework!