find the equation of the line through the two points (5, 3) and (-7,7)?

Answer 1

m = 4 / (- 12 ) = (- 1 / 3 )
y - 3 = (- 1 / 3) (x - 5)
y = (- 1 / 3 ) x + 5 / 3 + 9 / 3
y = (- 1 / 3 ) x + 14 / 3

Answer 2

The equation of a line is always given as y = mx + c where y is the y-coordinate, m is the gradient, x is the x-coordinate and c is the y-intercept.

So, to find the equation, you have to first find the gradient and the y-intercept.

Gradient = (y2 - y1)/ (x2 - x1)
= (7 - 3)/ (-7 - 5)
= 4/ (-12)
= - 1/3

To find the y-intercept, substitute in any one of the given 2 points.

So, let's say I use (5, 3)...

y = mx + c
(3) = (-1/3) * (5) + c
3 = -1 2/3 + c
=> c = 4 2/3

So, the equation will be y = -1/3x + 4 2/3

Hope that helps! :)

Answer 3

Let x1=5, x2=-7 & y1=3, y2=7

Now,
(x-x1)/(x1-x2)=(y-y1)/(y1-y2)
=> (x-5)/(5+7)=(y-3)/(3-7)
=> 12(x-5)=-4(y-3)
=> 12x-60=4y-12
=> 12x-4y=60-12
=> 12x-4y=48
=> 3x-y=12 is the required equation.

Answer 4

y= mx +c;
m= (y2-y1)/(x2-x1)
m= (-7-5)/(3-7)= -12/-4=3
y= 3x+c

let substute
(5,3)
5=3*3+c
c=5-9= -4


y =3x -4;

Answer 5

find first for the lope
m=(3-7)/(5+7)
=-4/12
m=-1/3
then use point slope
3((y-3)=-1/3(x-5)))3
3y-9=-(x-5)
3y-9=-x+5
in standard form
x+3y-14=0
in slope intercept
y=(-x+14)/3

Answer 6

the fastest way is to use this formulas:
(x-x1)/(x2-x1) = (y-y1)/(y2-y1)

(x-5)/(-7-5) = (y-3)/(7-3)
-->y= - x/3+14/3
SJSU mathlete

Answer 7

Your Face. Swish.