2007-09-27 19:24:28 · 6 answers · asked by ray 1 in Science & Mathematics ➔ Mathematics
y - 5 = (- 3) (x + 1)
y = - 3x - 3 + 5
y = - 3x + 2
2007-09-28 06:57:00 · answer #1 · answered by Como 7 · 0⤊ 0⤋
The line through (x1, y1) with slope m is given by the point-slope form :
y - y1 = m(x - x1)
Here we have
m = -3, x1 = -1, and y1 = 5
So the equation is:
y - 5 = -3(x + 1)
y - 5 = -3x - 3
y = -3x + 2
or you could write y + 3x = 2
2007-09-28 02:38:25 · answer #2 · answered by Christine P 5 · 0⤊ 0⤋
Plug in the points into
y = mx + b
5 = -3*-1 + b
5 = 3 + b
2 = b
y = -3x + 2
Hope this helps=]
2007-09-28 02:35:05 · answer #3 · answered by marikrismas 3 · 0⤊ 0⤋
y=mx+c
c=y-mx
c=5-(-3*-1)
c=5-3
c=2
eqn of line,
y=-3x+2
2007-09-28 02:35:03 · answer #4 · answered by ^^' 2 · 0⤊ 0⤋
y= -3x+2
y-5=-3(x--1)
y-5=-3x-3
y=-3x-3+5
y=-3x+2
2007-09-28 02:28:55 · answer #5 · answered by mylostpets 2 · 0⤊ 0⤋
i think it's:
y = -3x + 8
2007-09-28 02:29:14 · answer #6 · answered by yksnirk 1 · 0⤊ 0⤋