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I am between two: The value 1 >=Sinx>= -1. But which one of them is my limit at X approaching infinity

2007-09-27 18:55:33 · 7 answers · asked by wiz monk 1 in Science & Mathematics Mathematics

7 answers

Hm...... the sine wave...... values vary from -1 to 1.

Theres not really a limit for f(x) = sin x as x approaches infinity.

2007-09-27 18:59:53 · answer #1 · answered by Anonymous · 0 0

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RE:
what is lim sinx as x approaches positive infinity?
I am between two: The value 1 >=Sinx>= -1. But which one of them is my limit at X approaching infinity

2015-08-13 02:14:13 · answer #2 · answered by Anonymous · 0 0

sine x doesnt have a limit or it has an alternating limit depending on which math course you are in but most consider it not having a limit since sinx approaches -1 and 1

2007-09-27 19:05:19 · answer #3 · answered by jdale18 2 · 0 0

Lim Sin X

2016-12-29 04:02:24 · answer #4 · answered by ? 4 · 0 0

You take two sequences un and vn such as un=npi and vn=(2n+1)*pi/2, you know that the limit of a function is unique in continuous system, so in discret by a sequential interpretation, sin(un) goes to 0 when n goes to inf, and sin(vn) goes to 1 when n goes to inf, so you have to sequence which have the same limit in itself ( that to say inf ), which converge once put in sin toward two different limit, and by unicité of the limit, sin could not have a limit.

2015-05-13 05:04:33 · answer #5 · answered by Renard 1 · 0 0

None of them. Because sin x graph is periodic and never stop unless the boundary values is given.

But it is sure that sin x approaches x when x approaches zero.

2007-09-27 19:02:49 · answer #6 · answered by Lucky 4 · 0 0

you are correct in saying that the y-values fluctuate between 1 and -1. however, there is no limit to what x can be. so there is no answer.

If it was sin(x)/x however, and you were finding it's limit, it would equal 1.

2007-09-27 19:00:39 · answer #7 · answered by Anonymous · 0 0

Hi Monk,

sin x has no limit.

I got this problem wrong freshman year in calculus, and have never forgotten :-)

REgards,
Chas.

2007-09-27 19:01:44 · answer #8 · answered by Chas. 3 · 0 0

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