Hm...... the sine wave...... values vary from -1 to 1.
Theres not really a limit for f(x) = sin x as x approaches infinity.
2007-09-27 18:59:53
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answer #1
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answered by Anonymous
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This Site Might Help You.
RE:
what is lim sinx as x approaches positive infinity?
I am between two: The value 1 >=Sinx>= -1. But which one of them is my limit at X approaching infinity
2015-08-13 02:14:13
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answer #2
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answered by Anonymous
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sine x doesnt have a limit or it has an alternating limit depending on which math course you are in but most consider it not having a limit since sinx approaches -1 and 1
2007-09-27 19:05:19
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answer #3
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answered by jdale18 2
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Lim Sin X
2016-12-29 04:02:24
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answer #4
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answered by ? 4
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You take two sequences un and vn such as un=npi and vn=(2n+1)*pi/2, you know that the limit of a function is unique in continuous system, so in discret by a sequential interpretation, sin(un) goes to 0 when n goes to inf, and sin(vn) goes to 1 when n goes to inf, so you have to sequence which have the same limit in itself ( that to say inf ), which converge once put in sin toward two different limit, and by unicité of the limit, sin could not have a limit.
2015-05-13 05:04:33
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answer #5
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answered by Renard 1
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None of them. Because sin x graph is periodic and never stop unless the boundary values is given.
But it is sure that sin x approaches x when x approaches zero.
2007-09-27 19:02:49
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answer #6
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answered by Lucky 4
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you are correct in saying that the y-values fluctuate between 1 and -1. however, there is no limit to what x can be. so there is no answer.
If it was sin(x)/x however, and you were finding it's limit, it would equal 1.
2007-09-27 19:00:39
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answer #7
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answered by Anonymous
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Hi Monk,
sin x has no limit.
I got this problem wrong freshman year in calculus, and have never forgotten :-)
REgards,
Chas.
2007-09-27 19:01:44
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answer #8
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answered by Chas. 3
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