Graph consists of two straight lines that meet at (0 , 2).
Gradient of lines are 1 and - 1.
2007-09-28 03:42:07
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answer #1
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answered by Como 7
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The graph of an absolute value looks like a V, with the point at the origin. Adding a constant to x shifts the curve to the left. So you would draw a V with the point at (-2, 0).
2007-09-28 01:36:40
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answer #2
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answered by Anonymous
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well the graph of an absolute value looks like a V, with the point at the origin. Adding a constant to x shifts the curve to the left. So you would draw a V with the point at (-2, 0). good question good luck . -B-
2007-09-28 01:59:21
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answer #3
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answered by bubbles 3
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the graph will look like a "V" with the bottom point of the "V" at the point (-2,0).
The line will have a slope of -1/1 down the the point coming from the left, and a slope of 1/1 going up from the point to the right.
remember slope is rise/run.
so down one right one for -1/1
and up one right one for 1/1
2007-09-28 01:35:40
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answer #4
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answered by DK3 1
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It basically ends up looking like a V. The bottom of the V would be at (-2,0) and then it would go upwards with a slope of 1 (or -1) from that point.
I'm not sure if that's very clear... sorry if it isn't.
2007-09-28 01:36:58
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answer #5
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answered by RustyL71 4
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y = x+2 if x>=-2
y = -2-x if x<-2
This can also be done by plotting y=x+2 first, and plotting the mirror image (wrt the x axis) of the section left to y=0.
2007-09-28 01:36:12
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answer #6
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answered by Anonymous
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just start plotting points since your eq. is in the form of y=ax+b then you can pick any x you want plug it in and you get your y coordinate for example:
the bars on the end are absolute value meaning after plugging in your x and adding 2 then just make it positive
(0,2), (1,3), (2,5), (-1,1), (-2,0), (-3,1),(-4,2)
2007-09-28 01:36:28
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answer #7
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answered by jdale18 2
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they are stupid to teach such a thing
2007-09-28 01:34:32
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answer #8
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answered by Jack K 2
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