4 + [8 /x] + [4 /(x^2 )],
find F'( x ) ____
Then Find f'( 1 ) ___
2007-09-27 16:39:41 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
f ( x ) = 4 + 8x^(- 1) + 4x^(- 2)
f `( x ) = (- 8) x^(- 2) - 8 x^(- 3)
f `( x ) = (- 8) (1 / x ² + 1 / x ³ )
f `( x ) = (- 8) (x + 1) / x ³
f `(1) = (- 8) (2) / 1
f `(1) = - 16
2007-09-27 20:11:52 · answer #1 · answered by Como 7 · 1⤊ 0⤋
You can find f'(1) yourself. This is calculus, not Algebra 1.
f'(x)= -8/x^2 - 8/x^3 or -8/x^2 (1+1/x)
2007-09-27 23:45:11 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
f'(x)= [-8/(x^2)] - [8/(x^3)]
f'(1)=[-8/1^2] - [8/1^3]
= -8 - 8
= -16
2007-09-27 23:50:13 · answer #3 · answered by pride_rock21 2 · 0⤊ 0⤋
http://en.wikipedia.org/wiki/Table_of_derivatives
this site might be of help to you.. derivatives are fun to do- I don't want to steal the thunder from you
2007-09-27 23:43:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋