A car traveling at 7.0m/s accelerates 2.5m/s to reach a speed of 12.0m/s. How long does it take for this acceleration to occur?
my answer was 2.06
I divided the accelerations by the speed but I'm not sure if that was the right equation
2007-09-27 14:56:59 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
v1= 7.0 m/s
a= 2.5 m/s²
v2=12.0m/s
t=?
a = v2-v1 / t
t = v2- v1 / a
t= [12.0 m/s - 7.0 m/s] / [2.5m/s²]
t= [5.0 m/s] /[ 2.5 m/s²]
t= 2s
2007-09-27 15:02:00 · answer #1 · answered by WELDER® 5 · 0⤊ 0⤋
The acceleration is in meters per second squared (m/s²) -not- m/s (which is speed) and to get final speed it's
v = v0 + at so you have
12 = 7 + 2.5t
5 = 2.5t
2 = t
so the car accelerated for 2 seconds
Doug
2007-09-27 22:08:00 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋