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2007-09-27 14:48:30 · 4 answers · asked by diego 1 in Science & Mathematics Mathematics

4 answers

1/x < 2

1 < 2x

2x > 1

x > 1/2

interval type : open → x > a → (a,∞)

(1/2, ∞)

2007-09-27 14:56:17 · answer #1 · answered by WELDER® 5 · 0 0

One way you can do this is to setup a "related equation."
A related equation is nothing more than the same equation with an equal sign in it, instead of unequal sign.

1/x = 2

Now solve this and you get x = 1/2 or 0.5

Now, plug this into the original equation and you get:

1/(1/2) < 2

You'll notice, this isn't correct.... they are equal. In order for this to be true, the value X must be larger than what would make it equal.

Therefore x > 1/2

2007-09-27 21:56:00 · answer #2 · answered by tkquestion 7 · 0 0

1/x < 2
1 < 2x
1/2 < x

2007-09-27 22:05:13 · answer #3 · answered by The Glorious S.O.B. 7 · 0 0

1/x<2

If x > 0, then 1 < 2x
x > 1/2
x positive solution: x > 1/2

If x < 0, then 1 > 2x
x < 1/2
x negative solution: x < 0

All solutions: All reals less than 0 or all reals greater than 1/2

Interval notation: (-∞, 0) and (1/2, ∞)

2007-09-27 22:01:34 · answer #4 · answered by Marvin 4 · 0 0

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