Limits involving sin^2 help --- please help?

Question

if you guys can help me with a step by step i may beable to finish the rest, please help and thanks! Please tell me about your process because i dont get L'Hopital's rule...

l i m (sin^2 x) / (x)
x --> 0

Answer 1

l i m (sin^2 x) / (x)
x --> 0

This is a 0/0, so take derivatives of top and bottom:

d/dx( sinx)^2 = 2sinxcosx
d/dx(x) = 1

l i m (2sinxcosx) / (1) = 0
x --> 0

Answer 2

l i m (sin^2 x) / (x)
x --> 0
= lim (sin 2x)/1
x --> 0
= 0/1 =0