standard form??

Question

ok so i kno that standard form is ax + by = c

how woul di find the standard form of the equation of the line that passes through the oints (-5, 4) and (-8, -6)

Answer 1

Hi,
In a few syllables: Use the point-slope form of a linear equation, which is this:
y -y1 = m(x-x1) (Where m is the slope and (x1,y1) is either of the two points. Here's how to use it:
1) First we need the slope:
m = (y2-y1)/(x2-x1) (We can choose either point as (x1,y1)
m = (-6 -4)/(-8- (-5))
=-10/(-3)
= 10/3
So, now we plug that and one of the points, let's choose (-5,4), into
the equation:
y -4 = (10/3)(x- (-5))
y-4 =(10/3)(x +5)
3y-12= 10(x+5) (Multiply by 3)
3y -12 = 10x +50
-10x +3y = 50+12
-10x+3y =62
10x-3y = -62 (The first term must be positive.)

Hope this helps.
FE