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1. 16x^2 -y^2+96x+8y+112=0
2. y^2-4x^2-2y-16x+1=0

2007-09-27 12:21:28 · 1 answers · asked by Zoology 1 in Science & Mathematics Mathematics

1 answers

1.
16x² + 96x - y² + 8y + 112 = 0

16(x² + 6x) - (y² - 8y) +112 = 0

16[(x + 3)² - 9] - [(y - 4)² - 16] + 112 = 0

16(x + 3)² - 144 - (y - 4)² + 16 + 112 = 0

16(x + 3)² - (y - 4)² = 16

(x + 3)² - (y - 4)² /16 = 1

then the center is (-3 ; 4)

a = 1

b = 4

c = sqrt( 1 + 16) = sqrt(17)

e = c/a = sqrt(17)

and so on ...

2.
4x² + 16x - y² + 2y - 1 = 0

4(x + 2)² - (y - 1)² = 16

(x + 2)²/4 - (y - 1)²/16 = 1

the center is (-2 ; 1)

a = 2

b = 4

c = sqrt(20) = 2sqrt(5)

e = sqrt(5)

...

2007-09-28 05:10:45 · answer #1 · answered by Nestor 5 · 0 0

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