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walkway with uniform width (18ft by 16ft )
there is enough stone to cover 800 sqft of the hallway
There is to be a garden planted inside the walkway.

What will the width of the garden be?

2007-09-27 11:12:45 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

18 * 16 = 288

800 - 288 = 512

The garden needs to be
22.6 * 22.6 ft = 512 sqft

2007-09-27 11:19:10 · answer #1 · answered by petep73 3 · 0 0

Draw a rectangle labeled 18 by 16 feet. Now draw a rectangle within the first rectangle, labeled 18-2x by 16-2x. x here represents the width of the walkway around the garden, so 2x is the sum of the widths of the walkway on either side of the garden. The area of the walkway is the area of the whole thing minus the area of the garden, so:
800=18(16)-(18-2x)(16-2x)
800=288-(288-32x-36x-4x^2)
800=68x+4x^2
200=x^2+17x
It ends up with either 8 ft or -25 ft, but since you cannot have a negative width, it must be 8 feet. Now the width of the garden was 18-2(8). The width of the garden will be 2 ft.

2007-09-27 18:28:00 · answer #2 · answered by NerdHerd 2 · 0 0

Are the walkway and hallway the same thing?

If the garden is to be planted within the walkway, then its width must be <= 16 ft.

What do the 800 square feet of stones have to do with anything?

This question is not answerable. Please restate it as it was originally posed.

2007-09-27 18:29:55 · answer #3 · answered by ironduke8159 7 · 0 0

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